(1/2-x)^2+3x=1/4+x(x+2)

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Solution for (1/2-x)^2+3x=1/4+x(x+2) equation: 



(1/2-x)^2+3x=1/4+x(x+2)

We move all terms to the left:

(1/2-x)^2+3x-(1/4+x(x+2))=0



Domain of the equation: 2-x)^2!=0

We move all terms containing x to the left, all other terms to the right

-x)^2!=-2

x!=-2/1

x!=-2

x∈R





Domain of the equation: 4+x(x+2))!=0

We move all terms containing x to the left, all other terms to the right

x(x+2))!=-4

x∈R



We add all the numbers together, and all the variables

(-1x+1/2)^2+3x-(1/4+x(x+2))=0

We add all the numbers together, and all the variables

3x+(-1x+1/2)^2-(1/4+x(x+2))=0

We calculate fractions

There is no solution for this equation

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